To find the value of \( b \) in the quadratic equation \( x^2 + bx - 55 = 0 \) given the solutions \( -11 \) and \( 5 \), we can use Vieta's formulas. According to Vieta's, for a quadratic equation of the form \( x^2 + bx + c = 0 \):
- The sum of the roots is equal to \( -b \).
- The product of the roots is equal to \( c \).
Here, the solutions are \( -11 \) and \( 5 \).
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Sum of the roots: \[ -11 + 5 = -6 \] So, \( -b = -6 \) which gives \( b = 6 \).
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Product of the roots: \[ -11 \times 5 = -55 \] This supports that the value for \( c \) is indeed \(-55\).
Therefore, the value of \( b \) is \( 6 \).
The correct response is: 6.