To find the value of \( x \) where the perimeters of Raji's square and Ava's hexagon are equal, we can set up the equation based on their perimeters.
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Perimeter of the square:
The side length of the square is \( x + 5 \) cm.
Therefore, the perimeter of the square is:
\[ P_{\text{square}} = 4 \times (x + 5) = 4x + 20 , \text{cm} \] -
Perimeter of the hexagon:
The side length of the hexagon is \( x - 1 \) cm.
Therefore, the perimeter of the hexagon is:
\[ P_{\text{hexagon}} = 6 \times (x - 1) = 6x - 6 , \text{cm} \] -
Set the perimeters equal to each other:
\[ 4x + 20 = 6x - 6 \] -
Solve for \( x \):
\[ 20 + 6 = 6x - 4x \ 26 = 2x \ x = \frac{26}{2} = 13 \]
So the value of \( x \) is 13.