solving equation z²-6z+9=4√(z²-6z-6) following roots are obtained

Answer 1

Let put z=5
Z^2-6z+9=4√z^2-6z+6
25-30+9=4√25-30+6
4=4√1
4=4

Let put z=1
1-6+9=4√1-6+6
4=4
.....
Let put z=3+2√3
(3+2√3)^2-6(3+2√3)+9= 4√[(3+2√3)-6(3+2√3)+6]

(3^2+2√3^2+2×3×2√3)-6(3+2√3)+9=4√[(3^2+2√3^2+2×3×2√3)-6(3+2√3)+6]

9+12+12√3-18-12√3=
4 √(9+12+12√3-18-12√3+6)

12=4√9
12=4×3
12=12

(C) all the above

Answer 2

m²+2m+1=0
given:
(m-1)²=0

Answer 3

Z²-6z+5=0