solve y=2x^2+x-10

Answer 1

To solve the equation y = 2x^2 + x - 10, we need to find the values of x that make the equation true.

We can start by setting y = 0 and solving for x. This will give us the x-intercepts (or roots) of the equation.

Setting y = 0:

0 = 2x^2 + x - 10

Next, we can factor the quadratic equation or use the quadratic formula to find the values of x.

Factoring:
0 = (2x + 5)(x - 2)

Setting each factor equal to zero:

2x + 5 = 0 OR x - 2 = 0

Solving for x will give us two possible solutions:

For 2x + 5 = 0:
2x = -5
x = -5/2

For x - 2 = 0:
x = 2

Therefore, the solutions to the equation y = 2x^2 + x - 10 are x = -5/2 and x = 2.