To solve the equation y = 2x^2 + x - 10, we need to find the values of x that make the equation true.
We can start by setting y = 0 and solving for x. This will give us the x-intercepts (or roots) of the equation.
Setting y = 0:
0 = 2x^2 + x - 10
Next, we can factor the quadratic equation or use the quadratic formula to find the values of x.
Factoring:
0 = (2x + 5)(x - 2)
Setting each factor equal to zero:
2x + 5 = 0 OR x - 2 = 0
Solving for x will give us two possible solutions:
For 2x + 5 = 0:
2x = -5
x = -5/2
For x - 2 = 0:
x = 2
Therefore, the solutions to the equation y = 2x^2 + x - 10 are x = -5/2 and x = 2.
solve y=2x^2+x-10
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