Solve x2=78 by inspection. There are two real solutions. Enter the lesser number first, and use exponents in your responses

1 answer

To solve the equation \( x^2 = 78 \) by inspection, we need to find two numbers whose squares equal 78.

The two real solutions can be found by taking the square root of both sides:

\[ x = \pm \sqrt{78} \]

We can simplify \( \sqrt{78} \):

\[ \sqrt{78} = \sqrt{39 \times 2} = \sqrt{39} \cdot \sqrt{2} \]

However, for our purposes, we can leave it in radical form.

The two real solutions are:

\[ x = -\sqrt{78} \quad \text{and} \quad x = \sqrt{78} \]

Since we need to enter the lesser number first, the final answer is:

\[ -\sqrt{78}, \sqrt{78} \]

If you prefer the numerical approximation:

\[ -\sqrt{78} \approx -8.83 \quad \text{and} \quad \sqrt{78} \approx 8.83 \]

So in exact form, the solutions remain:

\[ -\sqrt{78}, \sqrt{78} \]