Asked by jerson

solve x^5-16=0 completely given that 2 solutions is 1 (hint there are 4 zeros)
Answered by Reiny
the real solution is x = cuberoot(16)
there are 4 complex roots, two of which are
(-2^.8 - 8000^.1)/4 ± 2sin(pi/5)i

check your typing, I don't really understand what you mean by
"given that 2 solutions is 1 "
Answered by Reiny
instead of <<the real solution is x = cuberoot(16) >>

I meant to say

the real solution is x = 5throot(16)
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