the real solution is x = cuberoot(16)
there are 4 complex roots, two of which are
(-2^.8 - 8000^.1)/4 ± 2sin(pi/5)i
check your typing, I don't really understand what you mean by
"given that 2 solutions is 1 "
solve x^5-16=0 completely given that 2 solutions is 1 (hint there are 4 zeros)
2 answers
instead of <<the real solution is x = cuberoot(16) >>
I meant to say
the real solution is x = 5throot(16)
I meant to say
the real solution is x = 5throot(16)