solve x + 21/2 < 8. make sure to write your inequality so that x comes first.

Answer 1

To solve the inequality \( x + \frac{21}{2} < 8 \), we can isolate \( x \).

1. Start by subtracting \( \frac{21}{2} \) from both sides:

\[ x < 8 - \frac{21}{2} \]

2. To perform the subtraction, we need to convert 8 into a fraction with a denominator of 2. We know that:

\[ 8 = \frac{16}{2} \]

3. Now we can subtract:

\[ x < \frac{16}{2} - \frac{21}{2} \]

4. Combine the fractions:

\[ x < \frac{16 - 21}{2} = \frac{-5}{2} \]

Thus, the final inequality where \( x \) comes first is:

\[ x < -\frac{5}{2} \]