x/x + 2/x ≥ .2
1 + 2/x ≥ .2
2/x ≥ -.8
2 ≥ -.8 x
-5/2 ≤ x
solve (x+2)/x>=0.2 with steps
4 answers
(x+2)/x >= 1/5
If x>0,
x+2 >= x/5
4x/5 >= -2
x >= -5/2
So, x > 0
If x<0,
x+2 <= x/5
4x/5 <= -2
x <= -5/2
So, x <= -5/2
So, in interval notation, x is in
(-∞,-5/2]U(0,∞)
If x>0,
x+2 >= x/5
4x/5 >= -2
x >= -5/2
So, x > 0
If x<0,
x+2 <= x/5
4x/5 <= -2
x <= -5/2
So, x <= -5/2
So, in interval notation, x is in
(-∞,-5/2]U(0,∞)
I found the same answer but answer is
x<-5/2
see on wolfram alpha
x<-5/2
see on wolfram alpha
thanks steve