To solve the equation \( x^2 = \frac{16}{25} \) by inspection, we can look for values of \( x \) that, when squared, equal \( \frac{16}{25} \).
We know that:
\[ x^2 = \frac{16}{25} \quad \implies \quad x = \pm \sqrt{\frac{16}{25}} \]
Calculating the square root:
\[ \sqrt{\frac{16}{25}} = \frac{\sqrt{16}}{\sqrt{25}} = \frac{4}{5} \]
Thus, the solutions for \( x \) are:
\[ x = \frac{4}{5} \quad \text{and} \quad x = -\frac{4}{5} \]
So, the solutions to the equation \( x^2 = \frac{16}{25} \) are:
\[ x = \frac{4}{5} \quad \text{or} \quad x = -\frac{4}{5} \]