To solve the inequality \( x + 15 \geq 3 \) and write it with \( x \) first, follow these steps:
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Subtract 15 from both sides of the inequality:
\[ x + 15 - 15 \geq 3 - 15 \]
Simplifying that gives:
\[ x \geq -12 \]
Now, the inequality is written with \( x \) first:
\[ x \geq -12 \]
This means that \( x \) can be any value greater than or equal to \(-12\).