Asked by Sydney
Solve
X + 1/x – 2 ≥ 3
I know you have to subtract the 3 from both sides to get the zero on right of the inequality sign. I don't understand how to make one fraction after I do this.
X + 1/x – 2 ≥ 3
I know you have to subtract the 3 from both sides to get the zero on right of the inequality sign. I don't understand how to make one fraction after I do this.
Answers
Answered by
Reiny
with brackets,
(x + 1)/(x – 2) ≥ 3
following your idea ...
(x + 1)/(x – 2) - 3 ≥
we need a common denominator of x-2
(x+1 -3x+6)/(x+1) ≥ 0
(-2x+7)(/(x-2) ≥ 0
so I see 2 critical values, x=7,2 and x=2
splitting the number line into 3 sections,
a) less than 7/2
b) between 7/2 and 2
c) greater than 2
pick any arbitrary value in each region, we don't actually have to evaluate it, just worry about the + or -
a) let x = 0 then +/- , does not work
b) let x = 3, then +/+ > 0 , YES
c) let x = 10, then -/+ , no way
so only the numbers between 7/2 and 2 work, but remember x cannot be 2 or else we are dividing by zer.
so the solution is
7/2 ≤ x < 2 , x is a real number
(x + 1)/(x – 2) ≥ 3
following your idea ...
(x + 1)/(x – 2) - 3 ≥
we need a common denominator of x-2
(x+1 -3x+6)/(x+1) ≥ 0
(-2x+7)(/(x-2) ≥ 0
so I see 2 critical values, x=7,2 and x=2
splitting the number line into 3 sections,
a) less than 7/2
b) between 7/2 and 2
c) greater than 2
pick any arbitrary value in each region, we don't actually have to evaluate it, just worry about the + or -
a) let x = 0 then +/- , does not work
b) let x = 3, then +/+ > 0 , YES
c) let x = 10, then -/+ , no way
so only the numbers between 7/2 and 2 work, but remember x cannot be 2 or else we are dividing by zer.
so the solution is
7/2 ≤ x < 2 , x is a real number
Answered by
Sydney
Thank you very much, you have been a great help!!!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.