To solve the inequality \( x - \frac{1}{3} \leq \frac{1}{2} \), we follow these steps:
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Add \( \frac{1}{3} \) to both sides: \[ x \leq \frac{1}{2} + \frac{1}{3} \]
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Find a common denominator (which is 6) to add the fractions: \[ \frac{1}{2} = \frac{3}{6} \quad \text{and} \quad \frac{1}{3} = \frac{2}{6} \] Thus, \[ \frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6} \]
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Now the inequality becomes: \[ x \leq \frac{5}{6} \]
Therefore, the solution is: \[ x \leq \frac{5}{6} \]
Among the provided responses, the correct one is: x less-than-or-equal-to Start Fraction 5 over 6 End Fraction.