To solve the inequality \( x - \frac{1}{3} \leq \frac{1}{2} \), we first isolate \( x \).
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Add \( \frac{1}{3} \) to both sides: \[ x \leq \frac{1}{2} + \frac{1}{3} \]
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Find a common denominator. The least common multiple of 2 and 3 is 6. Thus we can rewrite the fractions: \[ \frac{1}{2} = \frac{3}{6} \quad \text{and} \quad \frac{1}{3} = \frac{2}{6} \] Substituting these in gives: \[ x \leq \frac{3}{6} + \frac{2}{6} = \frac{5}{6} \]
So the solution to the inequality is: \[ x \leq \frac{5}{6} \]
Thus, the correct response is:
- x ≤ 5/6 (x less-than-or-equal-to Start Fraction 5 over 6 End Fraction)