2e^-x+4=21
2 e^-x = 17
e^-x = 17/2
1/e^x = 17/2
so
e^x = 2/17
take natural log of both sides
x = ln (2/17)
solve. we can use a calculator on this part...
2e^-x+4=21. how do i do this problem.
i know that you subtract 4, but what do you do after that?
3 answers
can you please show me how you got e^x=2/17. thanks
in general
a^-b = 1/a^b
a^-b = 1/a^b
2 answers