x^2 - 7x + 12 = 0
The 12 can factor into -3 and -4 to add to -7 in the middle term.
(x-3)(x-4) = 0
x = 3 or 4.
Solve using the quadratic formula.
a) x^2 - 7x + 12 = 0
a = 1 b = -7
x = -b +/- the sr of b^2 - 4ac /2a
7 +/- the sr of -7^2 - 4(1)(12) /2a
7 +/- the sr of -49 - 48 /2a
7 +/- the sr of -97 /2a
7 +/- 97 /2a
-90/2=-45
-104/2= 54
The roots are -45 and 54.
did i solve this correctly?
1 answer