We have the system of equations:
y = 2 + 3x
4x - 3y = -16
We can solve the first equation for y and substitute it into the second equation:
y = 2 + 3x
4x - 3(2 + 3x) = -16
Distribute the -3 to both terms inside the parentheses:
4x - 6 - 9x = -16
Combine like terms:
-5x - 6 = -16
Add 6 to both sides:
-5x = -10
Divide by -5:
x = 2
Now substitute this value of x back into the first equation to find y:
y = 2 + 3(2)
y = 2 + 6
y = 8
Therefore, the solution to the system of equations is x = 2 and y = 8.
Solve using substitution
y=2+3x
4x-3y=-16
1 answer