Solve using substitution.If the system has infinitely many solutions, express your answer in terms of k. If the system is inconsistent, enter INCONSISTENT.

Here is my work:

y=5x-5
5x-y=5

5x-(5x-5)=5
5x-5x+5=5
5=5

y=5x-5
k=5x-5
5x=k+5
x=1/5k+1

x,y = (k/5+1, 5k-5)

1 answer

Once you get to 5=5 you are done. There are infinitely many solutions.

If you put the two equations to the same format, they are

y = 5x-5
y = 5x-5

They are the same line. Any solution to one of them is also a solution to the other.
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