Ask a New Question
Search
solve using first differenciation principle
1)y=e^sinx
1 answer
the derivative of e^f(x)= e^f(x) . d/dx [f(x)]
therefore
y=e^sinx = e^sinx . cosx
Ask a New Question
or
answer this question
.
Similar Questions
solve using first principle of differenciation
1)y=e^3x 2)y=1/3(x^2)^1/2
1 answer
solve using first principle of differenciation
1)y=sin{square root(x)}
1 answer
Prove the following:
[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
3 answers
solve each equation for 0=/<x=/<2pi
sin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx
7 answers
more similar questions