solve using first differenciation principle

1)y=e^sinx

1 answer

the derivative of e^f(x)= e^f(x) . d/dx [f(x)]
therefore

y=e^sinx = e^sinx . cosx
Similar Questions
    1. answers icon 1 answer
    1. answers icon 1 answer
  1. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
    1. answers icon 3 answers
  2. solve each equation for 0=/<x=/<2pisin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx
    1. answers icon 7 answers
more similar questions