nothing to solve. However, if you meant
x^2-3x+4 = 0, the two complex values of x that make it true are
3/2 ± √7/2 i
If you meant to type
x^2-3x-4 = 0, then that factors to
(x-4)(x+1) = 0
and it should be clear which values of x are solutions there.
solve trinomial
x^2-3x+4
1 answer