Solve triangle ABC given the following conditions:

Question

1. C = 135.77 deg, b = 10cm, a = 12cm
2. a = 11.5m, b = 10m, c = 16.94m

Answer 1

in each case, use law of cosines to get c or C:

c^2 = a^2+b^2-2ab cosC

Now, having all 3 sides, and angle C, use law of sines to get A and B:

sinA/a = sinB/b = sinC/c