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solve system by matrices 2x+3y-z=-8 x-y-z=-2 -4x+3y+z=6Asked by jessica
solve this system by matrices
2x+3y-z=-8
x-y-z=-2
-4x+3y+z=6
2x+3y-z=-8
x-y-z=-2
-4x+3y+z=6
Answers
Answered by
Reiny
Jessica, it would be quite cumbersome to attempt typing matrices in this format.
Do you know how to find the inverse of a matrix?
Find it then multiply it by the column vector
-8
-2
6
Do you know how to find the inverse of a matrix?
Find it then multiply it by the column vector
-8
-2
6
Answered by
Reiny
here is one method to find the inverse
http://www.purplemath.com/modules/mtrxinvr.htm
Personally I use a method using adjoints, which seems very easy to do once you do it a few times.
On the other hand it is not easy to explain.
Here is a page where they try, but the first part might seem confusing.
They also form the adjoint at the end, I form it as my first step
http://www.easycalculation.com/matrix/inverse-matrix-tutorial.php
http://www.purplemath.com/modules/mtrxinvr.htm
Personally I use a method using adjoints, which seems very easy to do once you do it a few times.
On the other hand it is not easy to explain.
Here is a page where they try, but the first part might seem confusing.
They also form the adjoint at the end, I form it as my first step
http://www.easycalculation.com/matrix/inverse-matrix-tutorial.php
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