Solve this real-world problem using a system of equations. The O’Donnells are having a birthday party for their son, and they plan to have a clown bring balloons to the party. Balloon Express charges $2 per balloon and $10 for delivery. Balloon Mania charges $1.50 per balloon and $20 for delivery. If the O’Donnells plan to order 30 balloons, which company should they choose, and how much will they save?(1 point) Responses Balloon Mania; $5 Balloon Mania; $5 Balloon Express; $25 Balloon Express; $25 Balloon Mania; $25 Balloon Mania; $25 Balloon Express; $5

5 answers

Let's represent the number of balloons as x.

For Balloon Express, the total cost would be 2x + 10.
For Balloon Mania, the total cost would be 1.50x + 20.

We are given that the O'Donnells plan to order 30 balloons, so x = 30.

For Balloon Express, the total cost would be 2(30) + 10 = 70.
For Balloon Mania, the total cost would be 1.50(30) + 20 = 65.

Therefore, the O'Donnells should choose Balloon Mania, and they would save $5.
The Spanish Club at Santa Fe Middle School wants to sell mini quiches to raise money for a field trip. The culinary department at their school will make the quiches for $30 plus $0.50 per quiche for the ingredients. The Spanish Club wants to sell each quiche for $2. How many quiches will they need to sell in order to break even?(1 point) Responses 20 quiches 20 quiches 45 quiches 45 quiches 75 quiches 75 quiches 12 quiches
Let's represent the number of quiches as x.

The cost to make the quiches would be $30 + $0.50x.
The revenue from selling the quiches would be $2x.

To break even, the revenue should equal the cost:
$2x = $30 + $0.50x

Simplifying the equation:
$2x - $0.50x = $30
$1.50x = $30

Dividing both sides of the equation by $1.50:
x = $30 / $1.50
x = 20

Therefore, the Spanish Club will need to sell 20 quiches in order to break even. The correct response is "20 quiches."
The Baynard High School Boosters are selling hot dogs and pretzels at the concession stand. They have 300 hot dogs and pretzels in stock and want to earn an income of $800. They plan to sell the hot dogs for $4 each and the pretzels for $2 each. How many hot dogs and how many pretzels do the boosters need to sell to reach their goal of $800?(1 point) Responses 100 hot dogs and 200 pretzels 100 hot dogs and 200 pretzels 50 hot dogs and 250 pretzels 50 hot dogs and 250 pretzels 250 hot dogs and 50 pretzels 250 hot dogs and 50 pretzels 200 hot dogs and 100 pretzels
Let's represent the number of hot dogs as x and the number of pretzels as y.

The income from selling hot dogs can be represented as $4x.
The income from selling pretzels can be represented as $2y.

We are given that the boosters want to earn a total income of $800, so we can set up the following equation:

$4x + $2y = $800

We also know that there are 300 hot dogs and pretzels in stock, so:

x + y = 300

Now we have a system of equations:

$4x + $2y = $800
x + y = 300

To solve this system, we can use the substitution method.
Solve the second equation for x: x = 300 - y

Substitute this value of x into the first equation:

$4(300 - y) + $2y = $800
1200 - 4y + 2y = $800
-2y = $800 - $1200
-2y = -$400
y = -$400 / -2
y = 200

Now substitute the value of y into the second equation to find x:

x + 200 = 300
x = 300 - 200
x = 100

Therefore, the boosters need to sell 100 hot dogs and 200 pretzels to reach their goal of $800. The correct response is "100 hot dogs and 200 pretzels."