Solve this problem. Reduce to lowest terms.

Question

2 1 third÷1 3 over 8=

Answer 1

To solve this problem, we need to convert both fractions to improper fractions and then perform the division.

First, we convert 2 1/3 to an improper fraction:
2 1/3 = (2*3 + 1)/3 = 7/3

Next, we convert 1 3/8 to an improper fraction:
1 3/8 = (1*8 + 3)/8 = 11/8

Now, we can perform the division of 7/3 ÷ 11/8:

To divide fractions, we multiply the first fraction by the reciprocal of the second fraction:
7/3 ÷ 11/8 = 7/3 * 8/11

Now, we can multiply the numerators and denominators separately:
(7 * 8) / (3 * 11) = 56/33

However, this fraction is not in the lowest terms, so we need to further simplify it.

To simplify a fraction, we need to find the greatest common divisor (GCD) of the numerator and denominator and divide both by it.

The GCD of 56 and 33 is 1, so dividing both by 1 does not change the fraction:
56/33 = 56/33

Therefore, the solution, reduced to lowest terms, is 56/33.