Asked by fadil

solve this probability :a box contains 10 marble, seven of which are black and three are red.three marbles are drawn,one after the other without replacement. find the probability of choosing 1 red,1 black and 1 red marble. in that order
Answered by Reiny
prob(red, black, red)
= (3/10)(7/9)(2/8)
= 7/120
Answered by faith
a box contains 10 marble, seven of which are black and three are red.three marbles are drawn, one after the other without replacement. find the probability of choosing i. two black marbles
ii. at least two black marbles
iii. at most two black marbles.
note; please your explanation should be a detailed one
Answered by Nelson
3/10*7/9*2/8=7/120
Answered by Precious
A box contain 10 marbles 7 of which are Black and 3 are red. 3 marbles are drawn one after the other without replacement. Find the probability of choosing.A,one red one Black and one red in this other. B, two black marble.C,at least two black marbles. A, at most two black marbles.
Answered by Itunu
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