since sec^2 = 1+tan^2, you have
2+2tan^2 + tan^2-3 = 0
3tan^2 = 3
tan^2 = 1
tan = ±1
now, where is that true?
Solve the trigonometric equation from 0¡ã¡Üx¡Ü360
tanx+¡Ì3=0
2 sec^2x+tan^2x-3=0
1 answer
tanx+¡Ì3=0
2 sec^2x+tan^2x-3=0
1 answer