Solve the triangle ABC if angle A = 76 degrees and a = 12, b = 4

Answer 1

you have to use the law of sines which a/sinA=b/sin B=c/ sin C where the top letter is the opposite side of the angle and the lower letter is the angle itself. first you would go about solving this for angle B by putting 12/sin 76=4/ sin B. doing simple algebra the equation comes out to (4*sin(76))/12=sin B then you take the inverse sin of both sides to get angle B. Once you have angle B all the inside angle of a triangle equal 180 degrees so solve for angle C by taking 180-A-B=C. Then you go about solving for side c using the same equation to find Angle B except it would come out to look like (a*sin(C))/sin(A)=c. You want to use side a and angle A because those are given to you in the equation and will give the best result. Hope this helped!

Answer 2

(Tan²θ * sin²θ) + cos²θ +2sin²θ = sec²θ

Answer 3

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