To solve the system using elimination, we need to eliminate one variable by adding or subtracting the equations.
Multiply the first equation by 5:
5(6x-2y) = 5(28)
30x - 10y = 140
Now, multiply the second equation by 6:
6(5x + 7y) = 6(6)
30x + 42y = 36
By subtracting the second equation from the first, the x variable will be eliminated:
(30x - 10y) - (30x + 42y) = 140 - 36
30x - 10y - 30x - 42y = 104
-52y = 104
y = 104 / -52
y = -2
Now we can substitute the value of y back into one of the original equations:
6x - 2(-2) = 28
6x + 4 = 28
6x = 28 - 4
6x = 24
x = 24 / 6
x = 4
Therefore, the solution to the system of equations is (4, -2).
Solve the system using elimination.
6x-2y = 28
5x + 7y = 6
The solution is (Simplify your answer. Type an ordered pair.)
1 answer