Solve the system of two equations using substitution.

y=2+3x
4x−3y=−16(1 point)
Responses

(2, 10)
left parenthesis 2 comma 10 right parenthesis

(−2, 4)
left parenthesis negative 2 comma 4 right parenthesis

(−2, −4)
left parenthesis negative 2 comma negative 4 right parenthesis

(2, 8)

1 answer

(2, 8)

Start with the first equation y=2+3x and substitute it into the second equation:
4x - 3(2 + 3x) = -16
4x - 6 - 9x = -16
-5x - 6 = -16
-5x = -10
x = 2

Now substitute x back into the first equation to find y:
y = 2 + 3(2)
y = 2 + 6
y = 8

Therefore, the solution is (2, 8).
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