solve the system of the equation

x=6y-3
2x+7y=13

1 answer

To solve this system of equations, we will substitute the value of x from the first equation into the second equation.

x = 6y - 3

Substitute x = 6y - 3 into the second equation:

2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1

Now substitute y = 1 into the first equation to find the value of x:

x = 6(1) - 3
x = 6 - 3
x = 3

Therefore, the solution to the system of equations is x = 3 and y = 1.