To solve this system of linear equations, we can solve for one variable in the first equation and substitute it into the second equation.
From the first equation, we have y = x + 3.
Substituting this into the second equation:
-4x + 4(x + 3) = 28
-4x + 4x + 12 = 28
12 = 28
This equation is not possible because 12 is not equal to 28.
Therefore, there is no solution to this system of linear equations.
Solve the system of linear equations.
y=x+3
-4x+4y=28
3 answers
you did it wrong
Apologies for the mistake. Let's solve the system of equations correctly.
The given equations are:
1) y = x + 3
2) -4x + 4y = 28
From equation 1, we can substitute the value of y in equation 2:
-4x + 4(x + 3) = 28
Expanding the brackets:
-4x + 4x + 12 = 28
Combine like terms:
12 = 28
This equation is not possible since 12 is not equal to 28.
Therefore, the system of equations is inconsistent and does not have a solution.
The given equations are:
1) y = x + 3
2) -4x + 4y = 28
From equation 1, we can substitute the value of y in equation 2:
-4x + 4(x + 3) = 28
Expanding the brackets:
-4x + 4x + 12 = 28
Combine like terms:
12 = 28
This equation is not possible since 12 is not equal to 28.
Therefore, the system of equations is inconsistent and does not have a solution.
9 answers