To solve this system of linear equations by substitution, we need to substitute the value of y from the first equation into the second equation.
From the first equation: y = 4x - 45
Substitute y = 4x - 45 into the second equation:
4x - 45 = 3x - 7
4x - 3x = 45 - 7
x = 38
Now that we have found the value of x, we can substitute it back into the first equation to find y:
y = 4(38) - 45
y = 152 - 45
y = 107
Therefore, the solution to the system of linear equations is (38, 107).
Solve the system of linear equations by substitution.
{
y
=
4
x
−
45
y
=
3
x
−
7
(
26
,
107
)
(
38
,
89
)
(
38
,
107
)
(
26
,
113
)
1 answer
1 answer