To solve the system of equations:
1. First, write the equations in standard form:
6x - 3y = -6
9x - 3y = -18
2. Now, we can see that both equations have the same y-term with different coefficients. We can eliminate the y-term by subtracting the first equation from the second equation.
(9x - 3y) - (6x - 3y) = -18 - (-6)
3x = -12
x = -4
3. Now that we have the value of x, we can substitute it back into one of the equations to solve for y. Let's use the first equation:
6(-4) - 3y = -6
-24 - 3y = -6
-3y = 18
y = -6
Therefore, the solution to the system of equations is x = -4 and y = -6.
solve the system of equstions
6x - 3y = -6
9x - 3y = -18
1 answer
1 answer