Multiplying the first equation by 3 and the second equation by -5, we get:
(3)(-5x - y) = (3)(9)
-15x - 3y = 27
(-5)(3x - 5y) = (-5)(17)
-15x + 25y = -85
Adding the two equations together, the x terms will cancel out:
-15x - 3y + (-15x + 25y) = 27 + (-85)
-30x + 22y = -58
Since there is only one equation remaining, we consider it as "equation 1":
-30x + 22y = -58
To solve for y, isolate y:
22y = 30x - 58
y = (30x - 58)/22
y = 15x/11 - 29/11
Now, substitute this value of y back into equation 1 and solve for x:
-30x + 22(15x/11 - 29/11) = -58
-30x + 30x - 638/11 = -58
-638/11 = -58
Since this equation is not possible, there is no solution to the system of equations.
Solve the system of equations using elimination: minus, 5, x, minus, y, equals, 9−5x−y=9 and 3, x, minus, 5, y, equals, 173x−5y=17.
1 answer
1 answer