from the 2nd: x = 2y + 1
sub that into the 1st
(2y+1)^2 - 3y^2 = 13
4y^2 + 4y + 1 - 3y^2 - 13 = 0
y^2 + 4y - 12 = 0
it factors very nicely, and you will two values of y
sub each into x = 2y+1 to get their corresponding x values
Solve the system of equations. show your work.
x^2-3y^2=13 x-2y=1
2 answers
Thank you!! So much!