Solve the system of equations graphed on the coordinate axes below.

y, equals, start fraction, 3, divided by, 4, end fraction, x, minus, 7
y=
4
3

x−7
y, equals, minus, start fraction, 3, divided by, 4, end fraction, x, minus, 7
y=

4
3

x−7

1 answer

To solve this system of equations, we can set the two equations equal to each other and solve for x:

(3/4)x - 7 = -3/4x - 7

Multiplying both sides by 4 to eliminate the fractions, we get:

3x - 28 = -3x - 28

Adding 3x to both sides:

6x - 28 = -28

Adding 28 to both sides:

6x = 0

Dividing both sides by 6:

x = 0

Now that we have the value of x, we can substitute it back into either of the original equations to solve for y. Let's use the first equation:

y = (3/4)(0) - 7

y = -7

Therefore, the solution to the system of equations is x = 0 and y = -7.
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