To solve this system of equations by elimination, we first need to manipulate one or both equations so that when added or subtracted, one of the variables will be eliminated.
Let's multiply the first equation by 5 and the second equation by 3 to get:
15x + 30y = 105
-15x + 6y = 39
Now, add these two equations together to eliminate the x variable:
15x + 30y -15x + 6y = 105 + 39
36y = 144
y = 4
Now, substitute y = 4 back into the first equation to solve for x:
3x + 6(4) = 21
3x + 24 = 21
3x = -3
x = -1
Therefore, the solution to the system of equations is x = -1 and y = 4.
Solve the system of equations by equations
3x+6y=21
-5x+2y=13
1 answer
1 answer