Solve the system of equations at the right by the method of substitution. Verify your results by using a graphing utility. x2+y2-4x+6y-5=0, x+y+5=0
answer: x=-y-5
(-y-5)2+y2-4(-y-5)2+6y-5=0
y=√5-5, y=-5-√5
x+√5-5+5=0
x=-√5
x-5-√5+5=0
x=√5
y=√5-5, y=-5-√5, x=-√5, x=√5
how do i verify this?
3 answers
graph the equation, see where it crosses the x axis.
which equation do I graph?
Both of them. x2+y2-4x+6y-5=0, x+y+5=0
Most graphing utilities will let you plot one equation over another.
Here is one:
https://www.mathpapa.com/system-calculator.html
Put the equations in, where they overlap is a solution to both.
Most graphing utilities will let you plot one equation over another.
Here is one:
https://www.mathpapa.com/system-calculator.html
Put the equations in, where they overlap is a solution to both.
1 answer