just equate the two expressions for y:
x^2+2x = 3x+20
x^2-x-20 = 0
(x-5)(x+4) = 20
x = 5, -4
So the solutions are (5,35) and (-4,8)
Solve the system of equations algebraically. Show all of your steps.
y=x^2+2x
y=3x+20
5 answers
long foot
x^2+2x = 3x+20
x^2-x-20 = 0
(x-5)(x+4) = 20
x = 5, -4
x^2-x-20 = 0
(x-5)(x+4) = 20
x = 5, -4
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