Solve the system of equations.

–9x+y=12

2x+4y= −28
(1 point)
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1 answer

To solve the system of equations:

  1. \(-9x + y = 12\)
  2. \(2x + 4y = -28\)

We can solve one of the equations for one variable and then substitute it into the other equation.

Let's start with the first equation:

\[ y = 9x + 12 \]

Now, we will substitute \(y\) in the second equation:

\[ 2x + 4(9x + 12) = -28 \]

Now, distribute the \(4\):

\[ 2x + 36x + 48 = -28 \]

Combine like terms:

\[ 38x + 48 = -28 \]

Now, subtract \(48\) from both sides:

\[ 38x = -28 - 48 \] \[ 38x = -76 \]

Now, divide by \(38\):

\[ x = \frac{-76}{38} = -2 \]

Now that we have \(x\), we substitute it back to find \(y\):

\[ y = 9(-2) + 12 \] \[ y = -18 + 12 \] \[ y = -6 \]

So the solution to the system of equations is:

\[ \boxed{(-2, -6)} \]