To solve the system of equations, we can substitute the value of y from the second equation into the first equation and solve for x.
y = 10 + 4x
8x - 3(10 + 4x) = -22
8x - 30 - 12x = -22
Combine like terms:
-4x - 30 = -22
Add 30 to both sides:
-4x = 8
Divide both sides by -4:
x = -2
Now substitute this value of x back into the second equation to solve for y:
y = 10 + 4(-2)
y = 10 - 8
y = 2
Therefore, the solution to the system of equations is x = -2 and y = 2.
Solve the system of equations.
8x−3y= −22
y=10+4x
1 answer