Solve the system of equations.

8x−3y= −22
y=10+4x

1 answer

To solve the system of equations, we can substitute the value of y from the second equation into the first equation and solve for x.

y = 10 + 4x

8x - 3(10 + 4x) = -22
8x - 30 - 12x = -22

Combine like terms:
-4x - 30 = -22

Add 30 to both sides:
-4x = 8

Divide both sides by -4:
x = -2

Now substitute this value of x back into the second equation to solve for y:

y = 10 + 4(-2)
y = 10 - 8
y = 2

Therefore, the solution to the system of equations is x = -2 and y = 2.