Solve the system of equations. 8x−3y= −22 y=10+4x (1 point)

Answer 1

We can solve this system of equations by substituting the value of y from the second equation into the first equation.

From the second equation, we have y = 10 + 4x.

Substituting this into the first equation:

8x - 3(10 + 4x) = -22.

Now, we can distribute the -3:

8x - 30 - 12x = -22.

Combining like terms, we have:

-4x - 30 = -22.

Adding 30 to both sides:

-4x = 8.

Dividing by -4:

x = -2.

Now that we have the value of x, we can substitute it back into the second equation to find y:

y = 10 + 4(-2).

Simplifying:

y = 10 - 8.

y = 2.

Therefore, the solution to the system of equations is x = -2 and y = 2.

Answer 2

Solve the system of equations. 5x+2y=14 x−6y=22 (1 point)

Answer 3

We can solve this system of equations using the method of elimination or substitution.

Let's use the method of elimination.

First, we multiply the second equation by 5 to match the coefficients of x:

5(x-6y) = 5(22)
5x - 30y = 110

Now, we can subtract the first equation from this new equation:

(5x - 30y) - (5x + 2y) = 110 - 14

Simplifying:

-30y - 2y = 110 - 14
-32y = 96
y = -3

Now, we can substitute the value of y back into one of the original equations. Let's use the first equation:

5x + 2(-3) = 14
5x - 6 = 14
5x = 20
x = 4

Therefore, the solution to the system of equations is x = 4 and y = -3.

Answer 4

Solve the system of equations. –9x+y=12 2x+4y= −28 (1 point)

Answer 5

We can solve this system of equations using the method of substitution.

First, isolate y in the first equation:

-9x + y = 12
y = 9x + 12

Now substitute this expression for y in the second equation:

2x + 4(9x + 12) = -28

Simplify:

2x + 36x + 48 = -28

Combine like terms:

38x + 48 = -28

Subtract 48 from both sides:

38x = -76

Divide by 38:

x = -2

Now substitute the value of x back into the expression for y:

y = 9(-2) + 12
y = -18 + 12
y = -6

Therefore, the solution to the system of equations is x = -2 and y = -6.