To solve the system of equations, we can use the method of elimination. We can rearrange the second equation to have the same coefficient for y as the first equation:
9x - 3y = -18
-3y = -9x - 18
Dividing both sides by -3, we get:
y = 3x + 6
Now we can substitute this value of y into the first equation:
6x - 3(3x + 6) = -6
6x - 9x - 18 = -6
-3x - 18 = -6
-3x = 12
x = -4
Substituting this value of x back into the equation for y:
y = 3(-4) + 6
y = -12 + 6
y = -6
Therefore, the solution to the system of equations is (x, y) = (-4, -6).
Solve the system of equations.
6x−3y=−6
9x−3y=−18 (1 point)
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1 answer