To solve this system of equations, we can use the method of substitution or elimination.
First, let's use the elimination method to solve these equations.
First, we'll multiply the second equation by 2 to make the coefficients of y the same in both equations:
2(4x + 3y) = 2(-9)
8x + 6y = -18
Now, we need to eliminate y from one of the equations by multiplying the first equation by 3:
3(-6x + 2y) = 3(-32)
-18x + 6y = -96
Now, we can add the two equations together to eliminate y:
8x + 6y + -18x + 6y = -18 + -96
-10x = -114
x = 11.4
Now that we have found the value of x, we can substitute it back into one of the original equations. Let's use the first equation:
-6(11.4) + 2y = -32
-68.4 + 2y = -32
2y = 36.4
y = 18.2
Therefore, the solution to the system of equations is x = 11.4 and y = 18.2.
Solve the system of equations.−6x+2y=−324x+3y=−9(1 point)
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