To solve this system of equations, we can use the method of substitution or elimination. Let's choose the substitution method.
From the first equation:
-6x + 2y = -32
2y = 6x - 32
y = 3x - 16
Now, substitute y = 3x - 16 into the second equation:
4x + 3(3x - 16) = -9
4x + 9x - 48 = -9
13x - 48 = -9
13x = 39
x = 3
Now that we have found the value for x, we can substitute it back into the equation y = 3x - 16 to find y:
y = 3(3) - 16
y = 9 - 16
y = -7
Therefore, the solution to the system of equations is x = 3 and y = -7.
Solve the system of equations.
-6x+2y=-32
4x+3y=-9
1 answer