Solve the system of equations

Question

4x-8y=-36
-6x+y=32

Answer 1

We can solve this system of equations using either substitution or elimination method.

Let's use the elimination method:

First, let's multiply the second equation by 8 to make the coefficients of y in both equations the same:

-6x + y = 32
8(-6x + y) = 8(32)
-48x + 8y = 256

Now, our system of equations becomes:

4x - 8y = -36
-48x + 8y = 256

Now, add the two equations together:

(4x - 8y) + (-48x + 8y) = -36 + 256
-44x = 220
x = -5

Now that we have found the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the first equation:

4(-5) - 8y = -36
-20 - 8y = -36
-8y = -16
y = 2

Therefore, the solution to the system of equations is x = -5 and y = 2.