To solve the system of equations:
3x + 6y = 21
-5x + 2y = 13
We can use the method of substitution or elimination.
Let's use the method of substitution.
From the first equation:
3x + 6y = 21
Divide both sides by 3:
x + 2y = 7
x = 7 - 2y
Substitute x = 7 - 2y into the second equation:
-5(7 - 2y) + 2y = 13
-35 + 10y + 2y = 13
Combine like terms:
12y - 35 = 13
Add 35 to both sides:
12y = 48
Divide both sides by 12:
y = 4
Substitute the value of y = 4 into the first equation:
x + 2(4) = 7
x + 8 = 7
Subtract 8 from both sides:
x = -1
Therefore, the solution to the system of equations is x = -1 and y = 4.
Solve the system of equations. 3x+6y=21 –5x+2y=13
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