Solve the system of equations. 3x−4y=40 5x−5y=55(1 point) Responses (18, 7) left parenthesis 18 comma 7 right parenthesis (8,−3) left parenthesis 8 comma negative 3 right parenthesis (14, 3) left parenthesis 14 comma 3 right parenthesis (4,−7)

Answer 1

To solve this system of equations, we can use the method of substitution or elimination.
Let's use the substitution method:

3x - 4y = 40
5x - 5y = 55

Rearrange the first equation to solve for x:
3x = 4y + 40
x = (4/3)y + 40/3

Now substitute x in the second equation:
5((4/3)y + 40/3) - 5y = 55
20y/3 + 200/3 = 55

Multiply by 3 to get rid of the fractions:
20y + 200 = 165
20y = -35
y = -35/20
y = -7/4

Now substitute y back into the equation to solve for x:
x = (4/3)(-7/4) + 40/3
x = -7/3 + 40/3
x = 33/3
x = 11

Therefore, the solution to the system of equations is (11, -7/4) or (11, -1.75).