Solve the system of equations. 3x−4y=40 5x−5y=55 (1 point)

Answer 1

To solve the system of equations, we can use the method of substitution or elimination.

Let's use the method of substitution.

From the first equation, we can solve for x in terms of y.

3x - 4y = 40
3x = 4y + 40
x = (4y + 40)/3

Now we substitute this expression for x into the second equation:

5x - 5y = 55
5((4y + 40)/3) - 5y = 55
(20y + 200)/3 - 5y = 55
20y + 200 - 15y = 165
5y + 200 = 165
5y = 165 - 200
5y = -35
y = -35/5
y = -7

Now substitute this value of y back into the equation we found for x:

x = (4(-7) + 40)/3
x = ( -28 + 40 ) / 3
x = 12/3
x = 4

Therefore, the solution to the system of equations is x = 4 and y = -7.