Solve the system of equations. 3x−4y=40 5x−5y=55 (1 point) Responses (4,−7) left parenthesis 4 comma negative 7 right parenthesis (14, 3) left parenthesis 14 comma 3 right parenthesis (18, 7) left parenthesis 18 comma 7 right parenthesis (8,−3)

Answer 1

Let's solve the system of equations using the method of substitution:

From the first equation, we can solve for x in terms of y:
3x - 4y = 40
3x = 4y + 40
x = (4y + 40)/3

Now we substitute this expression for x into the second equation:
5x - 5y = 55
5((4y + 40)/3) - 5y = 55
(20y + 200)/3 - 5y = 55
(20y + 200) - 15y = 165
20y - 15y + 200 = 165
5y + 200 = 165
5y = -35
y = -7

Now substitute this value of y back into the expression for x:
x = (4(-7) + 40)/3
x = ((-28) + 40)/3
x = 12/3
x = 4

Therefore, the solution to the system of equations is (x, y) = (4, -7).