Solve the system of equations. 3x−4y=40 5x−5y=55 (1 point) Responses (14, 3) left parenthesis 14 comma 3 right parenthesis (8,−3) left parenthesis 8 comma negative 3 right parenthesis (4,−7) left parenthesis 4 comma negative 7 right parenthesis (18, 7)

Answer 1

To solve the system of equations, we can use either substitution or elimination method.

Let's use the substitution method:

From the first equation, we can isolate x:
3x - 4y = 40
3x = 4y + 40
x = (4y + 40)/3

Now substitute x in the second equation:
5x - 5y = 55
5((4y + 40)/3) - 5y = 55
(20y + 200)/3 - 5y = 55
20y + 200 - 15y = 165
5y + 200 = 165
5y = 165 - 200
5y = -35
y = -35/5
y = -7

Substitute y back into the first equation to find x:
x = (4(-7) + 40)/3
x = (-28 + 40)/3
x = 12/3
x = 4

Therefore, the solution to the system of equations is (4, -7).